Question

multiply.
$(4x^{2}+5)(6x^{2}+7)$

$(4x^{2}+5)(6x^{2}+7)=\square$

Explanation:

Step1: Apply FOIL method (First terms)

Multiply the first terms of each binomial:
$4x^2 \times 6x^2 = 24x^4$

Step2: Apply FOIL method (Outer terms)

Multiply the outer terms of the binomials:
$4x^2 \times 7 = 28x^2$

Step3: Apply FOIL method (Inner terms)

Multiply the inner terms of the binomials:
$5 \times 6x^2 = 30x^2$

Step4: Apply FOIL method (Last terms)

Multiply the last terms of each binomial:
$5 \times 7 = 35$

Step5: Combine like terms

Add the terms with $x^2$:
$28x^2 + 30x^2 = 58x^2$

Step6: Combine all terms

Assemble the final polynomial:
$24x^4 + 58x^2 + 35$

Answer:

$24x^4 + 58x^2 + 35$