Question

multiply.
$(x - 7)(x^2 - 6x + 3)$
$(x - 7)(x^2 - 6x + 3) = \square$

Explanation:

Step1: Distribute $x$ to each term

$x(x^2 - 6x + 3) = x^3 - 6x^2 + 3x$

Step2: Distribute $-7$ to each term

$-7(x^2 - 6x + 3) = -7x^2 + 42x - 21$

Step3: Combine all expanded terms

$x^3 - 6x^2 + 3x -7x^2 +42x -21$

Step4: Combine like terms

$x^3 + (-6x^2-7x^2) + (3x+42x) -21 = x^3 -13x^2 +45x -21$

Answer:

$x^3 - 13x^2 + 45x - 21$