Question

pemdas
1.) $7 + 2 \times 3 =$
2.) $(10 - 4) \div 2 =$
3.) $3^2 - 4 + 8 =$
4.) $(6 + 2) \times 3 - 5 =$
5.) $(3 + 5) \times 2 - 4^2 \div 4 =$
6.) $6 + (9 - 3) \times 2^2 \div 3 - 1 =$

Explanation:

Step1: Solve multiplication first

$2 \times 3 = 6$

Step2: Add to the remaining number

$7 + 6 = 13$

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Step1: Solve parentheses first

$10 - 4 = 6$

Step2: Divide by the remaining number

$6 \div 2 = 3$

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Step1: Calculate the exponent

$3^2 = 9$

Step2: Subtract then add left to right

$9 - 4 = 5$
$5 + 8 = 13$

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Step1: Solve parentheses first

$6 + 2 = 8$

Step2: Multiply by the remaining number

$8 \times 3 = 24$

Step3: Subtract the final number

$24 - 5 = 19$

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Step1: Innermost parentheses first

$3 + 5 = 8$

Step2: Multiply by the next term

$8 \times 2 = 16$

Step3: Subtract the inside constant

$16 - 4 = 12$

Step4: Calculate the outer exponent

$12^2 = 144$

Step5: Divide by the final number

$144 \div 4 = 36$

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Step1: Solve parentheses first

$9 - 3 = 6$

Step2: Calculate the exponent

$2^2 = 4$

Step3: Multiply the two results

$6 \times 4 = 24$

Step4: Divide by the remaining number

$24 \div 3 = 8$

Step5: Add and subtract left to right

$6 + 8 = 14$
$14 - 1 = 13$

Answer:

1. $13$
2. $3$
3. $13$
4. $19$
5. $36$
6. $13$