Question

simplify: $4(3y + 2) - 3(5y - 1)$
\\(\circ\\) a. $27y + 5$
\\(\circ\\) b. $2y + 11$
\\(\circ\\) c. $y + 10$
\\(\circ\\) d. $-3y + 11$

Explanation:

Step1: Apply distributive property

$4(3y + 2) = 12y + 8$; $-3(5y - 1) = -15y + 3$

Step2: Combine like terms

$(12y - 15y) + (8 + 3) = -3y + 11$

Answer:

d. $-3y + 11$