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Question
simplify. $sqrt{3} cdot sqrt{6}$
Step1: Combine square roots
$\sqrt{3} \cdot \sqrt{6} = \sqrt{3 \times 6}$
Step2: Multiply inside the root
$\sqrt{18}$
Step3: Factor out perfect square
$\sqrt{9 \times 2} = \sqrt{9} \cdot \sqrt{2}$
Step4: Simplify perfect square
$3 \cdot \sqrt{2}$
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$3\sqrt{2}$