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solve for b. $b + 3 = \\frac{1}{2}(b - 4)$ $b = \\square$

Question

solve for b.
$b + 3 = \frac{1}{2}(b - 4)$
$b = \square$

Explanation:

Step1: Eliminate the fraction

Multiply both sides by 2:
$$2(b + 3) = b - 4$$

Step2: Expand the left side

Distribute the 2:
$$2b + 6 = b - 4$$

Step3: Isolate b terms

Subtract $b$ from both sides:
$$2b - b + 6 = -4$$
$$b + 6 = -4$$

Step4: Solve for b

Subtract 6 from both sides:
$$b = -4 - 6$$

Answer:

$-10$