Question

$\sqrt{2x} + 3 = 9$

Explanation:

Step1: Isolate the square root term

Subtract 3 from both sides of the equation $\sqrt{2x} + 3 = 9$ to get $\sqrt{2x}=9 - 3$.
$\sqrt{2x}=6$

Step2: Eliminate the square root

Square both sides of the equation $\sqrt{2x}=6$ to get $(\sqrt{2x})^2 = 6^2$.
$2x = 36$

Step3: Solve for x

Divide both sides of the equation $2x = 36$ by 2 to get $x=\frac{36}{2}$.
$x = 18$

Answer:

$x = 18$