Question

$\sqrt3{12x + 28} = 4$
$x = \square$

Explanation:

Step1: Cube both sides to eliminate root

$$(\sqrt[3]{12x + 28})^3 = 4^3$$
$$12x + 28 = 64$$

Step2: Isolate the term with x

$$12x = 64 - 28$$
$$12x = 36$$

Step3: Solve for x

$$x = \frac{36}{12}$$

Answer:

$x = 3$