Question

$x + 3 + 4z = 36$
$x + 3y = 24$
$4x = 24$

Explanation:

Step1: Solve for x from third equation

$4x = 24$
$\frac{4x}{4} = \frac{24}{4}$
$x = 6$

Step2: Substitute x into second equation

$x + 3y = 24$
$6 + 3y = 24$
$3y = 24 - 6$
$3y = 18$
$\frac{3y}{3} = \frac{18}{3}$
$y = 6$

Step3: Substitute x into first equation

$x + 3 + 4z = 36$
$6 + 3 + 4z = 36$
$9 + 4z = 36$
$4z = 36 - 9$
$4z = 27$
$\frac{4z}{4} = \frac{27}{4}$
$z = \frac{27}{4}$

Answer:

$x=6$, $y=6$, $z=\frac{27}{4}$