Question

maya is selling raffle tickets. for every 4 tickets, she charges $32. complete the table below showing the number of tickets and the amount maya charges. number of tickets $square$ 4 7 $square$ 10 charge ($) 8 32 $square$ 72 $square$

Explanation:

Step1: Find the unit price per ticket

First, we know that 4 tickets cost $32. So the price per ticket is calculated by dividing the total charge by the number of tickets.
$\text{Price per ticket} = \frac{32}{4} = 8$ dollars per ticket. Wait, no, wait. Wait, when charge is $8, number of tickets? Wait, let's re-examine. Wait, when number of tickets is 4, charge is $32. So the rate is $32 for 4 tickets, so per ticket is $8? Wait, no, 32 divided by 4 is 8. Wait, but when charge is $8, how many tickets? Let's check the first row: charge $8, number of tickets? Let's find the relationship. Let's denote number of tickets as \( n \), charge as \( c \). From 4 tickets, $32, so the ratio \( \frac{c}{n} = \frac{32}{4} = 8 \). So \( c = 8n \), or \( n = \frac{c}{8} \).

Step2: Find number of tickets when charge is $8

Using \( n = \frac{c}{8} \), when \( c = 8 \), \( n = \frac{8}{8} = 1 \). So first blank (number of tickets) when charge is 8 is 1.

Step3: Find charge when number of tickets is 7

Using \( c = 8n \), when \( n = 7 \), \( c = 8 \times 7 = 56 \). So charge for 7 tickets is $56.

Step4: Find number of tickets when charge is $72

Using \( n = \frac{c}{8} \), when \( c = 72 \), \( n = \frac{72}{8} = 9 \). So number of tickets when charge is 72 is 9.

Step5: Find charge when number of tickets is 10

Using \( c = 8n \), when \( n = 10 \), \( c = 8 \times 10 = 80 \). So charge for 10 tickets is $80.

Answer:

Number of tickets	1	4	7	9	10

(So the blanks are: number of tickets: 1, 9; charge: 56, 80. Wait, the table has:

First column (number of tickets) first blank: 1 (since charge 8, n=8/8=1)

Third column (charge) for 7 tickets: 56 (8*7=56)

Fourth column (number of tickets) for charge 72: 9 (72/8=9)

Fifth column (charge) for 10 tickets: 80 (8*10=80))