QUESTION IMAGE
Question
3.2 measures of spread: standard deviation and variance
the table below gives the number of hours spent watching tv last week by a sample of 16 children. the values have been sorted. find the minimum, maximum, range, mean, and standard deviation of the following data.
the minimum, maximum, range should be entered as exact values.
round the mean and standard deviation to two decimals places.
|x|
|----|
|13|
|20|
|24|
|27|
|30|
|31|
|34|
|35|
|37|
|38|
|39|
|40|
|43|
|45|
|46|
|50|
min =
max =
range =
mean =
standard deviation =
Step1: Find minimum
The smallest value in the data - set is 13.
Step2: Find maximum
The largest value in the data - set is 50.
Step3: Calculate range
Range = Max - Min. So, Range = 50 - 13 = 37.
Step4: Calculate mean
The formula for the mean $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$, where $n = 16$ and $x_{i}$ are the data - points.
$\sum_{i=1}^{16}x_{i}=13 + 20+24 + 27+30+31+34+35+37+38+39+40+43+45+46+50=532$.
$\bar{x}=\frac{532}{16}=33.25$.
Step5: Calculate standard deviation
The formula for the sample standard deviation $s=\sqrt{\frac{\sum_{i = 1}^{n}(x_{i}-\bar{x})^{2}}{n - 1}}$.
First, calculate $(x_{i}-\bar{x})^{2}$ for each $x_{i}$:
$(13 - 33.25)^{2}=(-20.25)^{2}=410.0625$
$(20 - 33.25)^{2}=(-13.25)^{2}=175.5625$
$(24 - 33.25)^{2}=(-9.25)^{2}=85.5625$
$(27 - 33.25)^{2}=(-6.25)^{2}=39.0625$
$(30 - 33.25)^{2}=(-3.25)^{2}=10.5625$
$(31 - 33.25)^{2}=(-2.25)^{2}=5.0625$
$(34 - 33.25)^{2}=(0.75)^{2}=0.5625$
$(35 - 33.25)^{2}=(1.75)^{2}=3.0625$
$(37 - 33.25)^{2}=(3.75)^{2}=14.0625$
$(38 - 33.25)^{2}=(4.75)^{2}=22.5625$
$(39 - 33.25)^{2}=(5.75)^{2}=33.0625$
$(40 - 33.25)^{2}=(6.75)^{2}=45.5625$
$(43 - 33.25)^{2}=(9.75)^{2}=95.0625$
$(45 - 33.25)^{2}=(11.75)^{2}=138.0625$
$(46 - 33.25)^{2}=(12.75)^{2}=162.5625$
$(50 - 33.25)^{2}=(16.75)^{2}=280.5625$
$\sum_{i = 1}^{16}(x_{i}-\bar{x})^{2}=410.0625+175.5625+85.5625+39.0625+10.5625+5.0625+0.5625+3.0625+14.0625+22.5625+33.0625+45.5625+95.0625+138.0625+162.5625+280.5625 =1523$.
$s=\sqrt{\frac{1523}{16 - 1}}=\sqrt{\frac{1523}{15}}\approx\sqrt{101.5333}\approx10.08$.
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Min = 13
Max = 50
Range = 37
Mean = 33.25
Standard Deviation = 10.08