Question

from memory match the equation with its graph.
$f(x)=\sqrt{x}$

Explanation:

Step1: Identify domain of $f(x)=\sqrt{x}$

The square root function is only defined for $x\geq0$, so the graph exists only where $x$ is non-negative.

Step2: Identify key points of $f(x)$

Calculate values:

• When $x=0$, $f(0)=\sqrt{0}=0$
• When $x=1$, $f(1)=\sqrt{1}=1$
• When $x=4$, $f(4)=\sqrt{4}=2$

Step3: Match to correct graph

The bottom-left graph (unlabeled in the crop, the one starting at $(0,0)$ and curving upward slowly) matches the domain and key points, as it only exists for $x\geq0$ and passes through $(0,0)$, $(1,1)$, $(4,2)$.

Answer:

The graph in the bottom-left corner (the curve starting at the origin $(0,0)$ and increasing slowly for non-negative $x$ values)