Question

m is the midpoint of $overline{ad}$. what value of $x$ will make triangles abm and dcm congruent? 3 5 7 9

Explanation:

Step1: Use mid - point property

Since M is the mid - point of $\overline{AD}$, then $AM = DM$. Also, if $\triangle ABM\cong\triangle DCM$ (by Side - Side - Side congruence criterion assuming the other equal sides are given by the markings), we can set the non - mid - point related sides equal. That is, $3x + 6=4x - 1$.

Step2: Solve the equation for x

Subtract $3x$ from both sides: $3x+6-3x=4x - 1-3x$. This gives $6=x - 1$.

Step3: Isolate x

Add 1 to both sides: $6 + 1=x-1 + 1$. So, $x=7$.

Answer:

7