Question

molecular to empirical:
for each of the following compounds, identify the empirical formula. make sure to record the common factor
used to simplify the compound. an example has been done for you.

1. \\(\ce{p4o6}\\)

\\(\

$$\begin{array}{|c|c|} \\hline \\text{empirical formula} & \\text{factor} \\\\ \\hline \\ce{p2o3} & 2 \\\\ \\hline \\end{array}$$

\\)

1. \\(\ce{n4o2h6}\\)

\\(\

$$\begin{array}{|c|c|} \\hline \\text{empirical formula} & \\text{factor} \\\\ \\hline & \\\\ \\hline \\end{array}$$

\\)

1. \\(\ce{p12f3}\\)

\\(\

$$\begin{array}{|c|c|} \\hline \\text{empirical formula} & \\text{factor} \\\\ \\hline \\ce{p4f} & 3 \\\\ \\hline \\end{array}$$

\\)

1. \\(\ce{h6o5}\\)

\\(\

$$\begin{array}{|c|c|} \\hline \\text{empirical formula} & \\text{factor} \\\\ \\hline & \\\\ \\hline \\end{array}$$

\\)

1. \\(\ce{c9h3}\\)

\\(\

$$\begin{array}{|c|c|} \\hline \\text{empirical formula} & \\text{factor} \\\\ \\hline \\ce{c3h} & 3 \\\\ \\hline \\end{array}$$

\\)

1. \\(\ce{h5p10}\\)

\\(\

$$\begin{array}{|c|c|} \\hline \\text{empirical formula} & \\text{factor} \\\\ \\hline & \\\\ \\hline \\end{array}$$

\\)

Explanation:

Step1: Find GCF of 4,2,6

Greatest Common Factor (GCF) of 4, 2, 6 is 2.

Step2: Divide subscripts by GCF

For $\text{N}_4\text{O}_2\text{H}_6$: $\text{N}_{\frac{4}{2}}\text{O}_{\frac{2}{2}}\text{H}_{\frac{6}{2}} = \text{N}_2\text{O}\text{H}_3$

Step3: Find GCF of 6,5

GCF of 6 and 5 is 1.

Step4: Divide subscripts by GCF

For $\text{H}_6\text{O}_5$: $\text{H}_{\frac{6}{1}}\text{O}_{\frac{5}{1}} = \text{H}_6\text{O}_5$

Step5: Find GCF of 5,10

GCF of 5 and 10 is 5.

Step6: Divide subscripts by GCF

For $\text{H}_5\text{P}_{10}$: $\text{H}_{\frac{5}{5}}\text{P}_{\frac{10}{5}} = \text{H}\text{P}_2$

Answer:

1. Empirical Formula: $\text{N}_2\text{OH}_3$, Factor: 2
2. Empirical Formula: $\text{H}_6\text{O}_5$, Factor: 1
3. Empirical Formula: $\text{HP}_2$, Factor: 5