Question

molecular representation of a wildfire
balanced chemical equation of a wildfire:
$\ce{c6h12o6}$ + $\ce{o2}$ $\
ightarrow$ __ $\ce{co2}$ + __ $\ce{h2o}$

Explanation:

Step1: Balance Carbon atoms

In \( \ce{C6H12O6} \), there are 6 C atoms. So, we need 6 \( \ce{CO2} \) to balance C. So the coefficient of \( \ce{CO2} \) is 6.
\( \ce{C6H12O6 + O2 -> 6CO2 + H2O} \)

Step2: Balance Hydrogen atoms

In \( \ce{C6H12O6} \), there are 12 H atoms. Each \( \ce{H2O} \) has 2 H atoms. So, number of \( \ce{H2O} \) molecules needed is \( \frac{12}{2}=6 \). So coefficient of \( \ce{H2O} \) is 6.
\( \ce{C6H12O6 + O2 -> 6CO2 + 6H2O} \)

Step3: Balance Oxygen atoms

On the right side, total O atoms: \( 6\times2 + 6\times1 = 12 + 6 = 18 \). On the left side, \( \ce{C6H12O6} \) has 6 O atoms. Let the coefficient of \( \ce{O2} \) be \( x \). So, \( 6 + 2x = 18 \). Solving for \( x \): \( 2x = 18 - 6 = 12 \), so \( x = 6 \).
\( \ce{C6H12O6 + 6O2 -> 6CO2 + 6H2O} \)

Answer:

The balanced equation is \( \boldsymbol{\ce{C6H12O6 + 6O2 -> 6CO2 + 6H2O}} \) with coefficients 1, 6, 6, 6 (for \( \ce{C6H12O6} \), \( \ce{O2} \), \( \ce{CO2} \), \( \ce{H2O} \) respectively).