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on monday, forest avenue school surveyed some students about the types …

Question

on monday, forest avenue school surveyed some students about the types of pets they own. the results are shown in the bar graph below. bar - graph showing types of class pets with dogs having 25 students, cats having 35 students, birds having 10 students, fish having 15 students, other having 5 students. on tuesday, 45 more students took the same survey. assume that the proportional results shown on mondays graph will reflect the responses of the students surveyed on tuesday. what will be the difference between the number of students who own cats and the number of students who own dogs on tuesdays graph? a. 2 b. 5 c. 10 d. 20

Explanation:

Step1: Calculate total students on Monday

$25 + 35+10 + 15+5=90$

Step2: Calculate proportion of cat - owning students on Monday

Proportion of cat - owning students $=\frac{35}{90}=\frac{7}{18}$

Step3: Calculate proportion of dog - owning students on Monday

Proportion of dog - owning students $=\frac{25}{90}=\frac{5}{18}$

Step4: Calculate number of cat - owning students on Tuesday

Number of cat - owning students on Tuesday $=45\times\frac{7}{18}=17.5$

Step5: Calculate number of dog - owning students on Tuesday

Number of dog - owning students on Tuesday $=45\times\frac{5}{18}=12.5$

Step6: Calculate the difference

Difference $=17.5 - 12.5 = 5$

Answer:

B. 5