Question

moores law says that the number of transistors in a dense integrated circuit increases by 41% every year. in 1974, a dense integrated circuit was produced with 5000 transistors. which expression gives the number of transistors in a dense integrated circuit in 1979? choose 1 answer: a ( 5000 cdot 0.41^5 ) b ( 5000(1 + 0.41)^5 ) c ( 5000 + (1 + 0.41)^5 ) d ( 5000 + 0.41^5 )

Explanation:

Step1: Calculate time elapsed

$1979 - 1974 = 5$ years

Step2: Use compound growth formula

The annual growth rate is 41% or 0.41, so the growth factor per year is $1+0.41$. For 5 years, the total number of transistors is initial amount times growth factor raised to the number of years.

Answer:

B. $5000(1 + 0.41)^5$