QUESTION IMAGE
Question
the movement of the progress bar may be uneven because questions can be worth more or less (including zero) depending on your answer. a local doctor’s office logged the number of patients seen in one day by the doctor for ten days. find the mean, median, range, and midrange of the number of patients seen in ten days. 27 31 27 35 35 25 28 35 33 24 calculate the mean, median, range, and midrange of the number of patients seen in ten days.
○ mean, 29.5; median, 11; range, 29.5; midrange, 30
○ mean, 11; median, 29.5; range, 30; midrange, 29.5
○ mean, 29.5; median, 30; range, 29.5; midrange, 11
○ mean, 30; median, 29.5; range, 11; midrange, 29.5
Step1: Sort the data
Sort the number of patients: \(24, 25, 27, 27, 28, 31, 33, 35, 35, 35\)
Step2: Calculate the mean
Sum of data: \(24 + 25 + 27 + 27 + 28 + 31 + 33 + 35 + 35 + 35 = 300\)
Mean = \(\frac{\text{Sum}}{\text{Number of data points}} = \frac{300}{10} = 30\)
Step3: Calculate the median
For \(n = 10\) (even), median is average of 5th and 6th terms.
5th term: \(28\), 6th term: \(31\)
Median = \(\frac{28 + 31}{2} = \frac{59}{2} = 29.5\)
Step4: Calculate the range
Range = \(\text{Max} - \text{Min} = 35 - 24 = 11\)
Step5: Calculate the midrange
Midrange = \(\frac{\text{Max} + \text{Min}}{2} = \frac{35 + 24}{2} = \frac{59}{2} = 29.5\)
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Mean, 29.5; Median, 30; Range, 11; Midrange, 29.5 (Wait, let's recalculate properly. Wait, the data is 24, 25, 27, 27, 28, 31, 33, 35, 35, 35? Wait no, original data: 27, 31, 27, 35, 35, 25, 28, 35, 33, 24. Let's sort them: 24, 25, 27, 27, 28, 31, 33, 35, 35, 35. Wait, that's 10 numbers? Wait 24,25,27,27,28,31,33,35,35,35 – no, wait original data: 27,31,27,35,35,25,28,35,33,24. Let's count: 24,25,27,27,28,31,33,35,35,35? Wait no, 24,25,27,27,28,31,33,35,35,35 – that's 10 numbers? Wait 24,25,27,27,28,31,33,35,35,35: sum is 24+25=49, +27=76, +27=103, +28=131, +31=162, +33=195, +35=230, +35=265, +35=300. Wait sum is 300? Wait 24+25=49, 27+27=54 (49+54=103), 28 (131), 31 (162), 33 (195), 35+35+35=105 (195+105=300). So mean is 300/10=30? Wait no, wait original data: 27,31,27,35,35,25,28,35,33,24. Let's add again: 24+25=49, 27+27=54 (49+54=103), 28 (131), 31 (162), 33 (195), 35+35+35=105 (195+105=300). So sum is 300, mean is 300/10=30. Wait, median: since 10 numbers, median is average of 5th and 6th. Sorted data: 24,25,27,27,28,31,33,35,35,35. Wait 5th is 28, 6th is 31? Wait no, wait I sorted wrong. Wait 24,25,27,27,28, 31? No, 24,25,27,27,28, 31? Wait 24,25,27,27,28, 31, 33, 35, 35, 35. Wait 5th term is 28, 6th is 31? Then median is (28+31)/2=29.5. Range: max - min = 35 -24=11. Midrange: (max + min)/2=(35+24)/2=59/2=29.5. So the correct option is: Mean, 30; Median, 29.5; Range, 11; Midrange, 29.5. So the last option: Mean, 30; Median, 29.5; Range, 11; Midrange, 29.5.