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Question
mr. walker is looking at the fundraiser totals for the last five years. yearly fundraiser totals how does the mean of the totals compare to the median? the mean is $1.60 greater than the median. the mean is $2.82 greater than the median. the median is $2.82 greater than the mean. the median is $1.60 greater than the mean. year 1 2 3 4 5 total $896 $925 $880 $963 $914
Step1: Calculate the mean
First, find the sum of the fundraiser totals: \( 896 + 925 + 880 + 963 + 914 \)
\( 896+925 = 1821 \), \( 1821+880 = 2701 \), \( 2701+963 = 3664 \), \( 3664+914 = 4578 \)
Then, divide by the number of years (5) to get the mean: \( \frac{4578}{5} = 915.6 \)
Step2: Find the median
Arrange the totals in ascending order: \( 880, 896, 914, 925, 963 \)
The median is the middle value, which is the 3rd value, so the median is \( 914 \)
Step3: Compare mean and median
Subtract the median from the mean: \( 915.6 - 914 = 1.6 \)
So the mean is $1.60 greater than the median.
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The mean is $1.60 greater than the median.