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mr. walker is looking at the fundraiser totals for the last five years.…

Question

mr. walker is looking at the fundraiser totals for the last five years. yearly fundraiser totals how does the mean of the totals compare to the median? the mean is $1.60 greater than the median. the mean is $2.82 greater than the median. the median is $2.82 greater than the mean. the median is $1.60 greater than the mean. year 1 2 3 4 5 total $896 $925 $880 $963 $914

Explanation:

Step1: Calculate the mean

First, find the sum of the fundraiser totals: \( 896 + 925 + 880 + 963 + 914 \)
\( 896+925 = 1821 \), \( 1821+880 = 2701 \), \( 2701+963 = 3664 \), \( 3664+914 = 4578 \)
Then, divide by the number of years (5) to get the mean: \( \frac{4578}{5} = 915.6 \)

Step2: Find the median

Arrange the totals in ascending order: \( 880, 896, 914, 925, 963 \)
The median is the middle value, which is the 3rd value, so the median is \( 914 \)

Step3: Compare mean and median

Subtract the median from the mean: \( 915.6 - 914 = 1.6 \)
So the mean is $1.60 greater than the median.

Answer:

The mean is $1.60 greater than the median.