Question

multiple choice 2 points. consider the equilibrium shown below. when one looks at the equilibrium where x = ch₂ and the one where x = ch(ch₃)₂, how do the values of the equilibrium constants (k₀) compare? the k where x = ch₂ is greater. the ks differ only slightly and are both less than 1. the ks are equal. the k where x = ch(ch₃)₂ is greater.

Explanation:

Step1: Consider steric effects

Branched - chain substituents like CH(CH₃)₂ cause more steric hindrance.

Step2: Analyze equilibrium preference

The equilibrium will shift more towards the less - sterically hindered side. When X = CH(CH₃)₂, the more stable conformation (less steric strain) is more favored at equilibrium, resulting in a higher equilibrium constant compared to when X = CH₃.

Answer:

The K where X = CH(CH₃)₂ is greater.