Question

e and f are mutually exclusive events. p(e) = 0.91; p(f) = 0.42. find p(e | f)

Explanation:

Step1: Recall the definition of mutually - exclusive events

Mutually exclusive events mean $E\cap F=\varnothing$, so $P(E\cap F) = 0$.

Step2: Recall the formula for conditional probability

The formula for conditional probability is $P(E|F)=\frac{P(E\cap F)}{P(F)}$.

Step3: Substitute the values

Since $P(E\cap F) = 0$ and $P(F)=0.42$, then $P(E|F)=\frac{0}{0.42}=0$.

Answer:

$0$