Question

if a nacl salt bridge connected this half - cell to complete a voltaic cell, what ion would be released into the beaker?
initial state
final state
a. na⁺
b. cl⁻
enter the answer choice letter.

Explanation:

In a voltaic cell, the salt bridge maintains charge neutrality. Here, the copper half - cell: initial has more $\ce{Cu^{2+}}$, final has fewer (some $\ce{Cu^{2+}}$ reduced or reacted), so the solution becomes more negative (since $\ce{Cu^{2+}}$ is removed). To balance, anions (from salt bridge, $\ce{NaCl}$) will enter. $\ce{Cl^-}$ is the anion, so $\ce{Cl^-}$ is released.

Answer:

B. $\ce{Cl^-}$