Question

name the compound cuso₄. copper(i) sulfate copper(i) sulfite copper(ii) sulfite copper(ii) sulfate copper(iv) sulfate

Explanation:

1. First, identify the anion: In $\ce{CuSO4}$, the anion is $\ce{SO_4^{2-}}$, which is the sulfate ion (sulfite is $\ce{SO_3^{2-}}$).
2. Then, determine the charge of copper. The sulfate ion has a 2 - charge. For the compound to be neutral, copper must have a 2+ charge (since $1\times$ charge of Cu + $1\times$ charge of $\ce{SO_4^{2-}} = 0$; let charge of Cu be $x$, so $x + (-2)=0\Rightarrow x = + 2$).
3. So the compound is named by the cation (copper with +2 charge, so copper(II)) and the anion (sulfate).

Answer:

Copper(II) sulfate