Question

name: date: block: composite shapes parallelograms a = bh triangles a = 1/2bh find the area of each shape. write the formula, substitute, and solve. dont forget a label! 1. 7 cm 8 cm 11 cm 2.

Explanation:

Step1: Divide the shape into a rectangle and a triangle

The rectangle has base $b_1 = 11$ cm and height $h_1=8$ cm. The triangle has base $b_2 = 11$ cm and height $h_2 = 7$ cm.

Step2: Calculate the area of the rectangle

Using the formula for the area of a rectangle $A_{rect}=b_1h_1$, we substitute $b_1 = 11$ cm and $h_1 = 8$ cm. So $A_{rect}=11\times8 = 88$ $cm^{2}$.

Step3: Calculate the area of the triangle

Using the formula for the area of a triangle $A_{tri}=\frac{1}{2}b_2h_2$, we substitute $b_2 = 11$ cm and $h_2 = 7$ cm. So $A_{tri}=\frac{1}{2}\times11\times7=\frac{77}{2}=38.5$ $cm^{2}$.

Step4: Calculate the area of the composite - shape

The area of the composite shape $A = A_{rect}+A_{tri}$. So $A=88 + 38.5=126.5$ $cm^{2}$.

Answer:

$126.5$ $cm^{2}$