Question

name: jasean watts
date: 02/10/24
bell:
unit 4: linear equations
homework 3: graphing linear equations (day 1)
this is a 2-page document!
graph the following linear equations. convert to slope-intercept when necessary.

1. $y = -\frac{2}{5}x - 3$
2. $y = \frac{1}{2}x + 2$
3. $y = 6x - 5$
4. $y = -x + 1$
5. $y = -\frac{3}{4}x$
6. $y = -\frac{5}{4}x - 3$

study guide
bonnie sampson

Explanation:

Step1: Identify slope & y-intercept (Q4)

Equation: $y = -x + 1$, so slope $m=-1$, y-intercept $(0,1)$

Step2: Plot y-intercept (Q4)

Mark the point $(0,1)$ on the grid.

Step3: Use slope for 2nd point (Q4)

From $(0,1)$, move $\frac{-1}{1}$ (1 down, 1 right) to $(1,0)$.

Step4: Draw line (Q4)

Connect $(0,1)$ and $(1,0)$, extend both ends.

Step5: Identify slope & y-intercept (Q5)

Equation: $y = -\frac{3}{4}x$, so slope $m=-\frac{3}{4}$, y-intercept $(0,0)$

Step6: Plot y-intercept (Q5)

Mark the point $(0,0)$ on the grid.

Step7: Use slope for 2nd point (Q5)

From $(0,0)$, move $\frac{-3}{4}$ (3 down, 4 right) to $(4,-3)$.

Step8: Draw line (Q5)

Connect $(0,0)$ and $(4,-3)$, extend both ends.

Step9: Identify slope & y-intercept (Q6)

Equation: $y = -\frac{5}{4}x - 3$, so slope $m=-\frac{5}{4}$, y-intercept $(0,-3)$

Step10: Plot y-intercept (Q6)

Mark the point $(0,-3)$ on the grid.

Step11: Use slope for 2nd point (Q6)

From $(0,-3)$, move $\frac{-5}{4}$ (5 down, 4 right) to $(4,-8)$.

Step12: Draw line (Q6)

Connect $(0,-3)$ and $(4,-8)$, extend both ends.

Answer:

1. For $y=-\frac{2}{5}x-3$: Line passes through $(0,-3)$ and $(5,-5)$, extended.
2. For $y=\frac{1}{2}x+2$: Line passes through $(0,2)$ and $(2,3)$, extended.
3. For $y=6x-5$: Line passes through $(0,-5)$ and $(1,1)$, extended.
4. For $y=-x+1$: Line passes through $(0,1)$ and $(1,0)$, extended.
5. For $y=-\frac{3}{4}x$: Line passes through $(0,0)$ and $(4,-3)$, extended.
6. For $y=-\frac{5}{4}x-3$: Line passes through $(0,-3)$ and $(4,-8)$, extended.