Question

a net for a three - dimensional figure is shown on grid paper. each square of the grid paper represents 1 in.². area of rectangle: $a = lcdot w$. what is the surface area of the three - dimensional figure? s.a. =? in.². s.a. = $2(6cdot2)+2(6cdot3)+2(2cdot3)$

Explanation:

Step1: Calculate each product term

First, calculate \(2(6\cdot2)\): \(6\cdot2 = 12\), then \(2\times12 = 24\).
Next, calculate \(2(6\cdot3)\): \(6\cdot3 = 18\), then \(2\times18 = 36\).
Then, calculate \(2(2\cdot3)\): \(2\cdot3 = 6\), then \(2\times6 = 12\).

Step2: Sum the results

Add the three results together: \(24 + 36 + 12\).
\(24+36 = 60\), and \(60 + 12 = 72\).

Answer:

72