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Question
nitrate ion reacts with iodine, forming iodate ion and nitrogen dioxide gas.
\ce{no^-_{3} + i_{2} -> io^-_{3} + no_{2}}
which component is going through reduction?
a. \ce{no^-_{3}} b. \ce{i_{2}}
enter the answer choice letter.
To determine which component is reduced, we analyze the oxidation states. In \( \text{NO}_3^- \), nitrogen has an oxidation state of +5. In \( \text{NO}_2 \), nitrogen has an oxidation state of +4 (a decrease, indicating reduction). For \( \text{I}_2 \) (oxidation state 0) to \( \text{IO}_3^- \) (iodine oxidation state +5), iodine is oxidized (increase in oxidation state). So \( \text{NO}_3^- \) undergoes reduction.
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