Question

at noon the temperature was 6°c. over the next five hours the temperature dropped a total of 8 degrees. then every hour until 9:00 p.m. the temperature rose 4 degrees. what was the temperature at 9:00 p.m.? a 19°c b 12°c c 14°c d 10°c

Explanation:

Step1: Calculate temperature after drop

The initial temperature at noon is $6^{\circ}C$ and it drops $8^{\circ}C$ in 5 - hour period. So the temperature after the drop is $6 - 8=- 2^{\circ}C$.

Step2: Calculate number of hours from 5 pm to 9 pm

From 5 pm to 9 pm, there are $9 - 5 = 4$ hours.

Step3: Calculate temperature increase

The temperature rises $4^{\circ}C$ per hour for 4 hours. The total increase is $4\times4 = 16^{\circ}C$.

Step4: Calculate final temperature

Starting from $-2^{\circ}C$ and increasing by $16^{\circ}C$, the final temperature is $-2+16 = 14^{\circ}C$.

Answer:

C. $14^{\circ}C$