Question

now h⁺ can be neutralized using oh⁻ on both sides of the reaction. how many oh⁻ should be added to both sides of the reaction? ?oh⁻ + 4h⁺ + mno₄⁻ → mno₂ + 2h₂o + ?oh⁻

Explanation:

Step1: Identify H⁺ moles

There are 4 moles of \( H^+ \) on the left.

Step2: Neutralization ratio

Each \( H^+ \) reacts with 1 \( OH^- \) (\( H^+ + OH^-
ightarrow H_2O \)). So, to neutralize 4 \( H^+ \), we need 4 \( OH^- \) on both sides.

Answer:

4 (for both the left and right \( OH^- \) blanks)