Question

now that you have the b terms on one side, and a constant number on the other side, you need to isolate b to solve for the value of b. what move can you make to both sides of the equation to isolate b on the right side?
\\(\frac{2}{3}b + 9\\) = \\(b + 11\\)
\\(-\frac{2}{3}b\\) = \\(-\frac{2}{3}b\\)
\\(9\\) = \\(\frac{1}{3}b + 11\\)
\\(-11\\) = \\(-11\\)
\\(-2\\) = \\(\frac{1}{3}b\\)
subtract 2 from both sides
multiply both sides by b
multiply both sides by 3

Explanation:

Step1: Identify target equation

We start with the simplified equation after combining $b$ terms:
$$-2 = \frac{1}{3}b$$

Step2: Isolate $b$ via multiplication

Multiply both sides by 3 to cancel the fraction coefficient of $b$.
$$3 \times (-2) = 3 \times \frac{1}{3}b$$

Step3: Calculate final value

Simplify both sides to solve for $b$.
$$-6 = b$$

Answer:

The correct move is "Multiply both sides by 3", and the value of $b$ is $\boldsymbol{-6}$.