Question

5 numeric 1 point if $f(x) = h \circ j$ then $f(3) =?$ for all questions use the following functions: $g(x) = 3x + 2$ $h(x) = \frac{2}{x}$ $j(x) = x^2 - 1$

Explanation:

Step1: Recall the composition of functions

The composition \( f(x) = h \circ j \) means \( f(x) = h(j(x)) \). So we first need to find \( j(3) \), then substitute that result into \( h(x) \).

Step2: Calculate \( j(3) \)

Given \( j(x) = x^2 - 1 \), substitute \( x = 3 \):
\( j(3) = 3^2 - 1 = 9 - 1 = 8 \)

Step3: Calculate \( h(j(3)) = h(8) \)

Given \( h(x) = \frac{2}{x} \), substitute \( x = 8 \):
\( h(8) = \frac{2}{8} = \frac{1}{4} \)

Answer:

\(\frac{1}{4}\)