Question

1. an object free falls for 3.5 seconds. how far does it fall? 34.3 m 60.03 m 17.15 m 120.05 m

Explanation:

Step1: Identify the free - fall formula

The formula for the distance $d$ an object falls in free - fall is $d = \frac{1}{2}gt^{2}$, where $g$ is the acceleration due to gravity ($g = 9.8\ m/s^{2}$) and $t$ is the time.

Step2: Substitute the values

Given $t = 3.5\ s$ and $g=9.8\ m/s^{2}$, we substitute into the formula: $d=\frac{1}{2}\times9.8\times(3.5)^{2}$.
First, calculate $(3.5)^{2}=3.5\times3.5 = 12.25$.
Then, $\frac{1}{2}\times9.8\times12.25 = 4.9\times12.25$.
$4.9\times12.25 = 60.025\approx60.03\ m$.

Answer:

B. 60.03 m