Question

1. an object of mass 5.0 kg is lifted vertically upward by 2.0 m. assuming the acceleration due to gravity is 9.8 m/s², how much work is done against gravity?

a. 10 j
b. 20 j
c. 49 j
d. 98 j

Explanation:

Step1: Recall the formula for work done against gravity

The work done against gravity is given by the formula $W = mgh$, where $m$ is the mass, $g$ is the acceleration due to gravity, and $h$ is the height.

Step2: Substitute the given values into the formula

We are given $m = 5.0\space kg$, $g = 9.8\space m/s^{2}$, and $h = 2.0\space m$. Substituting these values into the formula, we get:
$W=(5.0\space kg)\times(9.8\space m/s^{2})\times(2.0\space m)$

Step3: Calculate the work done

First, multiply 5.0 and 9.8: $5.0\times9.8 = 49$. Then multiply the result by 2.0: $49\times2.0 = 98$. So the work done against gravity is $98\space J$.

Answer:

D. 98 J