Question

1. obtain 20 ml of 1 m sodium hydroxide in a 100 ml beaker.
2. using a 10 ml graduated cylinder, measure out 10 ml of the 1m hydrochloric acid solution.
3. pour this solution into a 50 ml beaker that is resting inside a 250 ml beaker.
4. place the temperature probe into the hydrochloric acid solution that is in the 50 ml beaker.
5. using the second 10 ml graduated cylinder, measure out 2 ml of the 1m sodium hydroxide solution. important: do not mix the two solution yet.
6. click collect to start the data collection.
7. let the program graph a few temperature readings, and then add the sodium hydroxide solution and stir the reaction mixture with the temperature probe.
8. after 30 seconds have elapsed, you may click stop to end data collection.
9. now we will examine the graph to determine the temperature change.

a. choose the statistics from the analyze menu and select temperature.
b. in the data table record the minimum and maximum temperatures.
c. calculate the temperature change and record in the data table.

1. dispose of the contents in the 50 ml beaker by placing in the large beaker in the cart.
2. repeat step 4 to 13 using the volume amounts from the data table.

data table

volume of hcl (ml)	volume of naoh (ml)	maximum temperature (°c)	minimum temperature (°c)	temperature change (°c)
2	10	23.8°c	22.4°c	1.4°c
6	6	25.8°c	22.2°c	3.6°c

Explanation:

Step1: Identify the task

The task is to analyze the temperature - change data in the table for different volumes of HCl and NaOH solutions.

Step2: Recall the formula for temperature change

The temperature change $\Delta T=T_{max}-T_{min}$.

Step3: Check the data in the table

For the first row: $T_{max} = 23.2^{\circ}C$, $T_{min}=22.2^{\circ}C$, so $\Delta T=23.2 - 22.2=1^{\circ}C$.
For the second row: $T_{max} = 23.8^{\circ}C$, $T_{min}=22.4^{\circ}C$, so $\Delta T=23.8 - 22.4 = 1.4^{\circ}C$.
For the third row: $T_{max} = 25.8^{\circ}C$, $T_{min}=22.2^{\circ}C$, so $\Delta T=25.8 - 22.2=3.6^{\circ}C$.

Answer:

The temperature - change values in the table are calculated correctly based on the formula $\Delta T=T_{max}-T_{min}$. For the three cases in the table, the temperature changes are $1^{\circ}C$, $1.4^{\circ}C$, and $3.6^{\circ}C$ respectively.