Question

one section of a football stadium has 10 seats in the front row, row a. each of the rows behind row a has 6 more seats than the row immediately in front of it. what is the total number of seats in rows a - e of the stadium? 34 110 44 220

Explanation:

Step1: Identify the number of seats in each row

Row A has 10 seats. Since each row behind row A has 6 more seats than the row in front of it, row B has $10 + 6=16$ seats, row C has $16 + 6 = 22$ seats, row D has $22+6=28$ seats, and row E has $28 + 6=34$ seats.

Step2: Calculate the total number of seats

The total number of seats in rows A - E is $10+16 + 22+28+34=\sum_{n = 0}^{4}(10+6n)$. Using the sum formula for an arithmetic - series $S_n=\frac{n(a_1 + a_n)}{2}$, where $n = 5$ (the number of rows from A to E), $a_1=10$ (seats in row A), and $a_5 = 34$ (seats in row E). So $S_5=\frac{5\times(10 + 34)}{2}=\frac{5\times44}{2}=110$.

Answer:

110