Question

one way you could solve this equation is by dividing first. show how you could divide both sides by the same number so that one group of $(x - 8)$ remains on the left. then, rewrite the equation.
$-6(x - 8) = -48$
$\frac{-6(x - 8)}{\square} = \frac{-48}{\square}$
$x - 8 = \square$

Explanation:

Step1: Identify divisor for left side

To isolate $(x-8)$, divide the coefficient $-6$ by itself. We divide both sides by $-6$.
$\frac{-6(x-8)}{-6} = \frac{-48}{-6}$

Step2: Simplify left side

The $-6$ terms cancel out, leaving $(x-8)$.
$\frac{-6(x-8)}{-6} = x-8$

Step3: Simplify right side

Calculate the division of the constants.
$\frac{-48}{-6} = 8$

Answer:

The filled-in equation steps are:
$\frac{-6(x - 8)}{\boldsymbol{-6}} = \frac{-48}{\boldsymbol{-6}}$
$x - 8 = \boldsymbol{8}$