Question

open - ended question
name the following:
1 - pb(clo₂)₄
2 - c₅n₃
3 - k₂s
type your answer here
rewatch

Explanation:

Step1: Identify cation and anion for $Pb(ClO_2)_4$

Lead ($Pb$) is the cation and chlorite ($ClO_2^-$) is the anion. Lead has a +4 oxidation - state here, so it's named lead(IV) chlorite.

Step2: Name $C_5N_3$

There is no common name for this compound. It is a binary compound of carbon and nitrogen. A possible name could be pentacarbon trinitride.

Step3: Identify cation and anion for $K_2S$

Potassium ($K^+$) is the cation and sulfide ($S^{2 - }$) is the anion. So it is named potassium sulfide.

Answer:

1. Lead(IV) chlorite
2. Pentacarbon trinitride
3. Potassium sulfide