Question

the organizers of a convention are drawing lots to pick the host city for the event. nine city names are written on different pieces of paper and placed in a bowl. the possible outcomes of drawing a name from the bowl are shown below. chicago seattle orlando dallas atlanta austin oakland phoenix cleveland what is the probability that cleveland or dallas is picked? a. options not clear b. options not clear c. options not clear d. options not clear

Explanation:

Step1: Determine total number of outcomes

There are 9 city - names, so the total number of possible outcomes $n(S)=9$.

Step2: Determine number of favorable outcomes

The favorable outcomes are picking Cleveland or Dallas. So the number of favorable outcomes $n(E) = 2$.

Step3: Calculate the probability

The probability formula is $P(E)=\frac{n(E)}{n(S)}$. Substituting the values, we get $P(E)=\frac{2}{9}$.

Answer:

The probability that Cleveland or Dallas is picked is $\frac{2}{9}$. Since the options are not clearly visible in the image, if we assume the options are in fraction form and one of them is $\frac{2}{9}$, that would be the correct option.