Question

orm the operation.
$(2x^2 - 3x + 1) + (7x^2 + 10x + 8)$

Explanation:

Step1: Remove parentheses

To add the two polynomials, we first remove the parentheses. Since there is a plus sign in front of both parentheses, the signs of the terms inside remain the same. So we have:
\(2x^{2}-3x + 1+7x^{2}+10x + 8\)

Step2: Combine like terms

Next, we combine the like terms. Like terms are terms with the same variable raised to the same power.

• For the \(x^{2}\) terms: \(2x^{2}+7x^{2}=(2 + 7)x^{2}=9x^{2}\)
• For the \(x\) terms: \(-3x+10x=(-3 + 10)x = 7x\)
• For the constant terms: \(1 + 8=9\)

Putting it all together, we get:
\(9x^{2}+7x + 9\)

Answer:

\(9x^{2}+7x + 9\)