Question

overall question: 1.890 g of benzoic acid, c₆h₅cooh, reacts in a calorimeter that contains 900. g of water. the temperature of the water increases from 30.00 to 38.32 °c. the heat capacity of the calorimeter is 2240 j/°c. the specific heat of water is 4.18 j/g °c. record data for each step. what is the δt for the water? δt = ? °c

Explanation:

Step1: Recall the formula for temperature change

The formula for the change in temperature \(\Delta T\) is the final temperature \(T_f\) minus the initial temperature \(T_i\), i.e., \(\Delta T = T_f - T_i\).

Step2: Identify the initial and final temperatures

The initial temperature \(T_i\) of the water is \(30.00^\circ\text{C}\) and the final temperature \(T_f\) is \(38.32^\circ\text{C}\).

Step3: Calculate \(\Delta T\)

Substitute the values into the formula: \(\Delta T = 38.32 - 30.00\)
\(\Delta T = 8.32^\circ\text{C}\)

Answer:

\(8.32\)