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Question
on your own: applications of right triangle
on your own
applications of right triangle trigonometry
now it’s time to practice on your own
at a certain time of the day, the angle of elevation of the sun is 18.5°.
what is the length of the shadow cast by your friend, who is 1.75 m tall?
round your answer to the nearest tenth of a meter.
enter your answer in the box.
Step1: Define trigonometric relationship
The friend's height is the opposite side, shadow length is the adjacent side to the elevation angle. Use tangent:
$\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}$
Step2: Rearrange for shadow length
Let $x$ = shadow length. Solve for $x$:
$x = \frac{1.75}{\tan(18.5^\circ)}$
Step3: Calculate the value
First compute $\tan(18.5^\circ) \approx 0.3346$, then:
$x \approx \frac{1.75}{0.3346} \approx 5.2$
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5.2 meters