Question

1. a paper airplane is thrown with an initial velocity of 2.4 m/s and an angle of 60°. find the $v_{oy}$. 2.32 m/s 1.70 m/s 2.08 m/s 1.2 m/s

Explanation:

Step1: Recall vertical - velocity formula

The formula for the initial vertical - velocity component is $v_{oy}=v_0\sin\theta$, where $v_0$ is the initial velocity and $\theta$ is the angle of projection.

Step2: Substitute given values

Given $v_0 = 2.4\ m/s$ and $\theta = 60^{\circ}$, and $\sin60^{\circ}=\frac{\sqrt{3}}{2}\approx0.866$. Then $v_{oy}=2.4\times\sin60^{\circ}=2.4\times0.866 = 2.0784\approx2.08\ m/s$.

Answer:

$2.08\ m/s$