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a parabola has a vertex at (-3,2). where is the axis of symmetry? y = 2…

Question

a parabola has a vertex at (-3,2). where is the axis of symmetry? y = 2 x = -3 y = -2 x = 3 43/50

Explanation:

Step1: Recall axis - of - symmetry property

The axis of symmetry of a parabola passes through its vertex. For a parabola with a vertex \((h,k)\), the equation of the axis of symmetry is \(x = h\) when the parabola opens vertically (either upwards or downwards).

Step2: Identify vertex coordinates

The vertex of the parabola is given as \((- 3,2)\), where \(h=-3\) and \(k = 2\).

Step3: Determine axis - of - symmetry equation

Since the axis of symmetry for a vertically - opening parabola is \(x=h\), substituting \(h=-3\) gives the equation \(x=-3\).

Answer:

\(x = - 3\)