Question

part 2 of 2\
3.75 g of methanol (ch₄o)\
3.75 g ch₄o = \square mol ch₄o

Explanation:

Step1: Calculate molar mass of \( \text{CH}_4\text{O} \)

Molar mass of \( \text{C} = 12.01 \, \text{g/mol} \), \( \text{H} = 1.008 \, \text{g/mol} \), \( \text{O} = 16.00 \, \text{g/mol} \).
Molar mass \( = 12.01 + 4\times1.008 + 16.00 = 32.042 \, \text{g/mol} \).

Step2: Use \( n = \frac{m}{M} \) to find moles

Given \( m = 3.75 \, \text{g} \), \( M = 32.042 \, \text{g/mol} \).
\( n = \frac{3.75}{32.042} \approx 0.117 \, \text{mol} \).

Answer:

\( 0.117 \) (or more precise \( \approx 0.117 \))