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part 1 collect and organize you have been given a lewis structure with …

Question

part 1
collect and organize
you have been given a lewis structure with connectivity c - s - s, including all valence electrons. you are asked to assign formal charges to the atoms.
analyze
remember that formal charge compares the electrons assigned to each atom with the valence electrons for the unbonded atom. the valence electrons for an unbonded atom of a main group element are determined from the group number.
part 2
collect and organize
you have been given a lewis structure with connectivity c - s - s, including all valence electrons. you are asked to assign formal charges to the atoms.
analyze
remember that formal charge compares the electrons assigned to each atom with the valence electrons for the unbonded atom. the valence electrons for an unbonded atom of a main group element are determined from the group number each atom is assigned all its nonbonding electrons and half the bonding electrons.

Explanation:

Step1: Determine valence electrons

Carbon (C) is in group 4, so it has 4 valence electrons. Sulfur (S) is in group 6, so each S - atom has 6 valence electrons.

Step2: Calculate formal charge formula

The formula for formal charge is $FC = V - N - \frac{B}{2}$, where $V$ is the number of valence electrons of the un - bonded atom, $N$ is the number of non - bonding electrons, and $B$ is the number of bonding electrons.

Step3: Assume a Lewis structure and count electrons

Let's assume a Lewis structure where C is double - bonded to one S and single - bonded to the other S. For the C atom: assume it has 0 non - bonding electrons ($N = 0$) and 6 bonding electrons ($B = 6$). Using the formula $FC_C=4 - 0-\frac{6}{2}=4 - 3 = 1$. For the S atom in the C = S double - bond: assume it has 4 non - bonding electrons ($N = 4$) and 4 bonding electrons ($B = 4$). Using the formula $FC_{S1}=6 - 4-\frac{4}{2}=6 - 4 - 2 = 0$. For the S atom in the C - S single - bond: assume it has 6 non - bonding electrons ($N = 6$) and 2 bonding electrons ($B = 2$). Using the formula $FC_{S2}=6 - 6-\frac{2}{2}=6 - 6 - 1=- 1$.

Answer:

The formal charge on C is + 1, on one S is 0, and on the other S is - 1.