Question

part a consider the figure: the ∠doe and ∠eob are
part b find the value of x. x = degrees

Explanation:

Step1: Recall angle - relationship definitions

Complementary angles add up to 90 degrees. Since $\angle DOB = 90^{\circ}$ and $\angle DOE+\angle EOB=\angle DOB$, $\angle DOE$ and $\angle EOB$ are complementary.

Step2: Calculate the value of $x$

We know that $\angle DOE = 32^{\circ}$ and $\angle DOE+\angle EOB = 90^{\circ}$. Let $x=\angle EOB$. Then $x = 90 - 32$.
$x=90 - 32=58$

Answer:

Part A: Complementary
Part B: 58