Question

part 2 of 4
$\ce{2h_{2}o_{2}(aq) -> 2h_{2}o(l) + o_{2}(g)}$

element	h	o

Explanation:

Step1: Calculate H atoms

In \(2H_2O_2\), H atoms: \(2\times2 = 4\). In products (\(2H_2O + O_2\)), H atoms: \(2\times2 = 4\) (from \(2H_2O\)). So total H atoms: 4.

Step2: Calculate O atoms

In \(2H_2O_2\), O atoms: \(2\times2 = 4\). In products: \(2H_2O\) has \(2\times1 = 2\) O, \(O_2\) has 2 O. Total O: \(2 + 2 = 4\).

Answer:

For H: 4; For O: 4