Question

part b
enter the equation from part a in the form ( ax^2 + bx + c = 0 ).
enter the correct equation in the box.
show hints
( 1x^2 + 5x + 6 = 0 )

Explanation:

Step1: Identify the quadratic form

The standard quadratic equation is \(ax^{2}+bx + c = 0\). The given equation in the box is \(1x^{2}+5x + 6 = 0\) (assuming the intended constant term is 6, as the numbers available are 1,5,6 for \(a = 1\), \(b = 5\), \(c = 6\) to form a valid quadratic equation \(x^{2}+5x + 6=0\) which factors as \((x + 2)(x+3)=0\) and is in the form \(ax^{2}+bx + c = 0\) with \(a = 1\), \(b = 5\), \(c = 6\)).

Step2: Confirm the form

We check that the equation \(x^{2}+5x + 6 = 0\) is in the form \(ax^{2}+bx + c = 0\) where \(a = 1\), \(b = 5\), and \(c = 6\).

Answer:

\(x^{2}+5x + 6 = 0\)