Question

part 3 of 3 how many moles of c₂h₄ are needed to form 0.92 mol of co₂? \square mol c₂h₄

Explanation:

Step1: Identify the reaction

Assume the combustion reaction of \( \ce{C2H4} \): \( \ce{C2H4 + 3O2 -> 2CO2 + 2H2O} \). From the reaction, 1 mol of \( \ce{C2H4} \) produces 2 mol of \( \ce{CO2} \). Wait, but the problem is about forming \( \ce{CO} \)? Wait, maybe a typo, but if we assume the reaction for \( \ce{CO} \), maybe incomplete combustion: \( \ce{C2H4 + O2 -> 2CO + 2H2} \) (simplified). Then 1 mol \( \ce{C2H4} \) gives 2 mol \( \ce{CO} \). But the problem says "form 0.92 mol of \( \ce{CO} \)". Wait, maybe the correct reaction is for \( \ce{CO2} \), but the problem has \( \ce{CO} \). Wait, maybe it's a typo, but let's proceed with the given. Wait, the formula is \( \ce{C2H4} \) (ethylene). Let's assume the reaction where \( \ce{C2H4} \) forms \( \ce{CO} \), say \( \ce{C2H4 + O2 -> 2CO + 2H2} \). Then mole ratio \( \ce{C2H4} : \ce{CO} = 1:2 \).

Step2: Calculate moles of \( \ce{C2H4} \)

Given moles of \( \ce{CO} = 0.92 \) mol. From mole ratio, moles of \( \ce{C2H4} = \frac{\text{moles of } \ce{CO}}{2} \). So \( \frac{0.92}{2} = 0.46 \) mol. Wait, but maybe the reaction is different. Wait, maybe the problem is about \( \ce{CO2} \), but the user wrote \( \ce{CO} \). Alternatively, maybe the reaction is \( \ce{C2H4 -> 2C + 2H2} \), no. Wait, perhaps the original problem is about \( \ce{CO2} \), but the user mistyped. But based on the given, if we take the mole ratio as 1:2 (1 mol \( \ce{C2H4} \) produces 2 mol \( \ce{CO} \)), then moles of \( \ce{C2H4} = \frac{0.92}{2} = 0.46 \) mol.

Answer:

\( 0.46 \) mol \( \ce{C2H4} \) (assuming mole ratio 1:2 between \( \ce{C2H4} \) and \( \ce{CO} \))