Question

part c
the momentum of an object is determined to be 7.2×10⁻³ kg·m/s. express this quantity as provided or use any equivalent unit (note: 1 kg = 1000 g).
specify the units of your answer. review a list of acceptable units.
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Explanation:

Step1: Identify the given value

The given momentum is $7.2 \times 10^{-3} \space kg \cdot m/s$. We can also convert the units if needed, but the problem allows using the provided unit or an equivalent. The SI unit of momentum is $kg \cdot m/s$, and we can also express it in $g \cdot m/s$ by converting kilograms to grams. Since $1 \space kg = 1000 \space g$, we have:
$7.2 \times 10^{-3} \space kg \times \frac{1000 \space g}{1 \space kg} = 7.2 \space g$. So the momentum can be written as $7.2 \times 10^{-3} \space kg \cdot m/s$ or $7.2 \space g \cdot m/s$. But we can present the value as given or in an equivalent unit. Let's use the given value's magnitude and unit or convert. Wait, the problem says "express this quantity as provided or use any equivalent unit". So the value is $7.2 \times 10^{-3}$ and the unit is $kg \cdot m/s$, or we can convert $kg$ to $g$:

Step2: Convert kg to g (optional, but let's check)

Given $1 \space kg = 1000 \space g = 10^3 \space g$. So $7.2 \times 10^{-3} \space kg = 7.2 \times 10^{-3} \times 10^3 \space g = 7.2 \space g$. So the momentum can be $7.2 \space g \cdot m/s$ or $7.2 \times 10^{-3} \space kg \cdot m/s$. Both are equivalent. Let's present the value as $7.2 \times 10^{-3}$ with unit $kg \cdot m/s$ or $7.2$ with unit $g \cdot m/s$.

Answer:

Value: $7.2 \times 10^{-3}$ (or $7.2$ if converting kg to g)
Units: $kg \cdot m/s$ (or $g \cdot m/s$)

(If we use the given unit without conversion, the value is $7.2 \times 10^{-3}$ and unit is $kg \cdot m/s$. If we convert, value is $7.2$ and unit is $g \cdot m/s$)